Question

60 points

Answer if you know... Otherwise I will report it... Spammers get lost.. Its urgent.. Answer with explanation...

The number of terms between 11 and 200 which are divisible by 7 but not by 3 are
1. 18
2. 19
3. 27
4. 28

Answer it with explanation. I will mark BRAINLIEST...

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Answer 1

I think I can answer it

Answer :

Step-by-step explanation:

The formula is

$m = \frac{tm - t1 + p}{p}\\ m=the\: no \: of \: terms \\tm=the \: last \: term \: which \: is \: divisible \: by \\ p \: just \: before \: tx \\ p = the \: number \: by \: which \: divisible \\ where \: mth \: term \: before \: tx \: divisible \\ by \: p \\ tx = given \: last \: term \\ t1 = 1st \: term \: divisible \: by \: p \: after \\ t \\ t = given \: starting \: term$

So

$m1 = \frac{196 - 14 + 7}{7} \\ = \frac{189}{7} = 27$

m1 is no of terms divisible by 7

Again

$m2 = \frac{189 - 21 + 21}{21} \\ = \frac{189}{21} = 9 \\ \\ here \: m2 =no \: of \: terms \: divisible \\ by \: both \: 7 \: and \: 3 \: that \: means \: 21$

So the number of terms which are only divisible by 7 can be found if we subtract m2 from m1 = 27-9 =18

Answer 2

Answer:

Step-by-step explanation:

Sn=n/2+[2a+(n-1)d]

Mth= a+(m-1)d

Hope it helps you...

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