Question

60 points. Pls solve this . Question in photo

Answer 1

In triangle acb, By pythagoras theorem, c^2=a^2+b^2......... eqn 1

We have to prove that, 1/psquare=1/asquare+1/bsquare

Let us simplify this...

1/p^2= a^2+b^2/(ab)^2

1/p^2=c^2/(ab)^2 ( from eqn 1)

(cp)^2=(ab)^2 so we have to prove this only!!!!

( i have done this bcz the problem will become simpler after this step)

in triangles, adc and acb, by aa similarity,

b/c=p/a

= cp=ab

Then, square on both sides,

That finally gives our proof, (cp)^2=(ab)^2

Answer 2

Hey mate here is your answer

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In triangle acb, By pythagoras theorem, c^2=a^2+b^2......... eqn 1

We have to prove that, 1/psquare=1/asquare+1/bsquare

Let us simplify this...

1/p^2= a^2+b^2/(ab)^2

1/p^2=c^2/(ab)^2 ( from eqn 1)

(cp)^2=(ab)^2 so we have to prove this only!!!!

( i have done this bcz the problem will become simpler after this step)

in triangles, adc and acb, by aa similarity,

b/c=p/a

= cp=ab

Then, square on both sides,

That finally gives our proof..........

□■□■□■□■□■□■□■□■□□■□■□

Hope you like it....

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