Math, asked by DaniyalaNikitayadav, 7 months ago

60. The median of the observation 1.8, 1.0.2.7, 1.2, 4.5, 2.3.3.7. 3.1 is
61. The average marks of 150 students in a class is 60, the average marks of the boys in the class is 70 and that of the digits
is 55, then the number of girls in the class is
62. The mode of 10 values is 36. ir 5 is subtracted from cach of the 10 values then the mode is
63. Less than cumulative curves are drawn using
64. The Arithmetic Mean of a +2, a, and a – 2 is
65. The difference between maximum and minimum of the class intervals is called
66. The mean of 9, 11, 13, p. 18, 19 is p then the value of p is
67. For a construction of a frequency polygon and frequencies are taken into consideration
68. In a frequency distribution the mid-value of the class is 35 and the lower boundan is 30. then its upper boundary is
cumulative frequencies are
69. In a greater than cumulative frequency distribution boundary of classes
taken.
70. For a given data Mode = a; Median = b; then the Mean -​

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Answered by Anonymous
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