Question

60.. The number of proper subsets of the set with
cardinality 3 is
(A) 8
(B) 7
(C) 6
(D) 3​

Answer 1

Answer:

(B) 7

Step-by-step explanation:

option 7 is correct as no of proper subsets= 2^n-1

now here n=3

so no. of proper subsets=2³-1

=8-1=7

hope it helps....

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Answer 2

$\huge\fbox\color{gold}{ANSWER}$

The number of proper subset of a given set is given by

$= {2}^{n} - 1$

Given n = 3

$= {2}^{3} - 1$

$= 8 - 1$

$= 7$

Hence Option-B is correct