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[tex]/box{Tex}{/tex}
★ Area of ∆ = 1/2(Base)(Height
⟹ ar(ADC) = 1/2(18)(4.3)⟹ ar(ADC) = 9(4.3)
⟹ ar(ADC) = 38.7 cm²
Similarly
,⟹ ar(ABC) = 1/2(18)(5.6)
⟹ ar(ABC) = 9(5.6)
⟹ ar(ABC) = 50.4 cm²
∴ Area of ABCD = ar(ADC + ABC)
➭ Area of quadrilateral = 38.7 + 50.4 = 89.1 cm²
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