Question

600 mL of aqueous solution containing 2.5 g of a protein shows an osmotic pressure
of 25 mm Hg at 27°C. Determine the relative molecular mass of protein.
​

Answer 1

relative molecular mass of protein is 3116 g/mol

It has given that 600 mL of aqueous solution containing 2.5 g of a protein shows an osmotic pressure of 25 mm Hg at 27°C.

we have to determine the relative molecular mass of protein.

osmotic pressure, P = 25 mm Hg = 25/760 atm

volume , V = 600 mL = 0.6 L

temperature, T = 27°C = 300K

mass of protein, w = 2.5 g

let molecular mass of protein is M.

now using formula, PV = nRT

⇒25/760 × 0.6 = (2.5/M) × 0.082 × 300

⇒6/760 = 24.6/M

⇒M = 24.6 × 760/6 = 3116 g

therefore relative molecular mass of protein is 3116 g/mol

Answer 2

Answer:

relative molecular mass of protein is 3116 g/mol

It has given that 600 mL of aqueous solution containing 2.5 g of a protein shows an osmotic pressure of 25 mm Hg at 27°C.

we have to determine the relative molecular mass of protein.

osmotic pressure, P = 25 mm Hg = 25/760 atm

volume , V = 600 mL = 0.6 L

temperature, T = 27°C = 300K

mass of protein, w = 2.5 g

let molecular mass of protein is M.

now using formula, PV = nRT

⇒25/760 × 0.6 = (2.5/M) × 0.082 × 300

⇒6/760 = 24.6/M

⇒M = 24.6 × 760/6 = 3116 g

therefore relative molecular mass of protein is 3116 g/mol