Question

600/(x-200) - 600/x = 30/60 then x = ?​

Answer 1

Answer:

Function to maximize: Z=1000x+600y

Constraints: x+y≤200

4x−y≤0

x≥20

x≥0,y≥0

Corner Points Values of Z=1000x+600y at corner points

(20,80) 68000

(20,180) 110000

(40, 160) 136000 ← Maximum

Hence, the maximum value of Z=1000x+600y is 136000.

Answer 2

Step-by-step explanation:

600

$600 \div (x - 200) - 600 \div x = 30 \div 60$

600(x) - 600(x-200)/ (x-200)(x) =1/2

600x- 600x- 180000/ x^2 - 200x =1/2

cross multiplication of LHS and RHS

x^2-200x = 2(-180000)

x^2 - 200x = -360000

x^2-200 x +360000=0

next u can solve as you wish

1. quadratic formula

2. factorisation

HOPE IT HELPS YOU :)