Question

₹6000 for 2 years rate9% per annum compunded anually​

Answer 1

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Amount=7128.6 \:rupees}}$

${\bold{\therefore Compound\:interest=1128.6 \:rupees}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

• In the given question information given about principal , rate and time is given.

• We have to find the Amount and Compound interest.

$\underline \bold{Give n : } \\ \implies Principal(p) = 6000 \: rupees \\ \\ \implies Time(t) = 2 \: years \\ \\ \implies Rate(R) = 9\% \\ \\ \underline \bold{To \: Find : } \\ \implies Compound \: interest = ?$

• According to given question :

$\bold{Using \: formula \: of \: compound \: interest : } \\ \implies A= p(1 + \frac{R}{100} ) ^{t} \\ \\ \implies A = 6000 \times (1 + \frac{9}{100} ) ^{2} \\ \\ \implies A = 6000 \times (\frac{100 + 9}{100} ) ^{2} \\ \\ \implies A = 600 0\times \frac{109}{100} \times \frac{109}{100} \\ \\ \bold{\implies A = 7128.6 \: rupees} \\ \\ \bold{For \: compoud \: interest : } \\ \implies Compound \: interest = Amount - Principal \\ \\ \implies C.I= 7128.6 - 6000 \\ \\ \bold{ \implies C.I = 1128.6 \: rupees}$

Answer 2

ANSWER:-

Given:

⚫Principal,(P)=Rs.6000

⚫Time, (n)= 2 years

⚫Rate, (r)= 9% p.a.

Therefore,

We know that, Formula of Compound Interest;

=) C.I.= Amount - Principal

&

Amount:

$A = P(1 + \frac{r}{100} ) {}^{n} \\ \\ = > 6000(1 + \frac{9}{100} ) {}^{2} \\ \\ = > 6000( \frac{100 + 9}{100} ) {}^{2} \\ \\ = > 6000( \frac{109}{100} ) {}^{2} \\ \\ = > 6000 \times \frac{109}{100} \times \frac{109}{100 } \\ \\ = > \frac{6 \times 109 \times 109}{10} \\ \\ = > Rs.\frac{71286}{10} \\ \\ = > Rs.7128.6$

Now,

C.I= A - P

C.I= Rs.7128.6 - Rs.6000

C.I.= Rs.1128.6

Thus,

•Amount= Rs.7128.6

•Compound Interest= Rs.1128.6.

Hope it helps ☺️