Question

₹ 6000 lent at 12% p.a compoundes anually for 3/2 years

Answer 1

hope its helpful..............

Answer 2

Step-by-step explanation:

Since we have given that

Sum = Rs. 6000

Rate of interest = 125

Time = 3/2 years

We first find the amount for 1 year.

So, it becomes,

$amount \: = \: {p(r + \frac{1}{100} )}^{n} \\ = > 6000(1 + \frac{12}{100} ) \\ = > 6000(1 + 0.12) \\ 6000(1.12) \\ = 6720$

So, now, it becomes principal for next half year, and we will apply simple interest rule:

So, our equation becomes,

$i = \frac{6720 \times 12 \times 1}{200} \\ = 403.2$

So, Amount = 6720 + 403.20 = 7123.20

Hence, Rs. 6000 becomes Rs. 7123.20

after 3/2 years

Hope it may help you