Question

6000 Pa pressure is exerted by 2 m vertical column of a liquid. Calculate the density. ( g = 10​

Answer 1

Answer:

$\boxed{\mathfrak{Density \ of \ liquid \ (ρ) = 300 \ kg/m^3 }}$

Given:

Height of vertical column (h) = 2 m

Hydrostatic pressure (P) = 6000 Pa

Acceleration due to gravity (g) = 10 m/s²

To Find:

Density of liquid (ρ)

Explanation:

Pressure due to liquid column:

$\boxed{ \bold{P = \rho gh}}$

Substituting value of P, g & h in the equation:

$\sf \implies 6000 = \rho \times 10 \times 2 \\ \\ \sf \implies 6000 = 20 \rho \\ \\ \sf \implies 20 \rho = 6000 \\ \\ \sf \implies \rho = \frac{6000}{20 } \\ \\ \sf \implies \rho = 300 \: kg/ {m}^{3}$

$\therefore$

Density of liquid (ρ) = 300 kg/m³

Answer 2

Answer:

P = 6000 Pa

h = 2 m

g = 10 m/s²

P = rho gh

rho = P/gh

= 6000/(2 ×10)

= 300 kg/m³

Density = 300 kg/m³