Question

600m+400n=15;260m+240n=3 solve by linear equations in two variables​

Answer 1

Step-by-step explanation:

Given:

600m + 40n = 15

260m + 240n = 3

Solution:

Using elimination method we have:

Step 1:

Write down the equation.

600m + 40n = 15. ......................(i)

260m + 240n = 3. ......................(ii)

Step 2:

Make the co-efficient of either m and n in both the equation.

13(600m + 40n = 15)

30(260m + 240n = 3)

or

6(600m + 40n = 15)

260m + 240n = 3

Step 3:

Write down the equation after making the co-efficient equal.

7800m + 520n = 195 ..................(iii)

7800m + 7200n = 90 ..................(iv)

or

3600m + 240n = 90 ...................(iii)

260m + 240n = 3 .... ..............(iv)

Step 4:

Subtract equation (iii) - (iv)

7800m + 520n = 195

- 7800m + 7200n = 90

- 6680n = 105

n = -105/6680

n = -21/ 1336

or

3600m + 240n = 90

- 260m + 240n = 3

3340m = 87

m = 87/3340

Step 5:

(a) Put the value of n in any of the equation (i) or (ii)

260m + 240n = 3

260m + 240 × -21/1336 = 3

260m + -630/ 187 = 3

260m = 3 + 630/187

260m = (561 + 630)/187

260m = 1191/187

m = 1191/187 × 1/260

m= 87/3340

or

(b) Put the value of m in any of the equation (i) or (ii)

600m + 40n = 15

600 × 87/ 3340 + 40n = 15

2610/137 + 40n = 15

40n = 15 - 2610/137

40n = (2055 - 2610)/137

40n = -555/137

n = -555/ 137 × 1/40

n = -21/1336

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