Question

600ml mixture and 52% acid how to convert 80 % acid

Answer 1

Acid present in mixture
= 600/100×52
=6×52
=312
Therefore
1%=312/52
=6

Such that 80%
=6×80
=480
Hence ,489ml is acid

Answer 2

Answer : The 840 ml of acid should be added to the 600 ml of the mixture to change the mixture from 52% acid to 80% acid.

Solution :

First we have to calculate the initial amount of acid.

Initial amount of acid = $600\times \frac{52}{100}=312ml$

Now we have to calculate the amount of pure acid should be added.

Let the amount of pure acid added be 'x' and the equation become,

$(312+x)=\frac{80}{100}\times (600+x)$

By solving the term x, we get

x = 840

Hence, the 840 ml of acid should be added to the 600 ml of the mixture to change the mixture from 52% acid to 80% acid.