60g of acetic acid is present in 540g of water. Calculate mole fraction of each component.
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Answer:
acetic acid =1 /10
water = 9/10
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Explanation:
molar mass of acetic acid is 60g
molar mass of water is 18g
no of moles of acetic acid = 60/60 = 1
no of moles of water = 18/540 = 1/30
mole fraction of acetic acid = n of acetic acid / (n of acetic acid + n of water)
= 1/ (1+1/30)
= 30/31
= 0.968
mole fraction of water = n of water / (n of water + n of acetic acid)
= (1/30) / (1/30 +1)
= 1/31
= 0.032
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