60g of ice at 0 degree Celsius is mixed with 60g of steam at 100 degree Celsius . At thermal equilibrium, the mixture contains, how many gms of water or steam at what temperature......?? Its very urgent please solve
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There is no water because of steam the 60 gms ice turn into steam
Therefore 60 +60 =120 gms
120 gms steam formed
Therefore 60 +60 =120 gms
120 gms steam formed
prathabadami:
the key answer for this is 80g of water and 40g of steam at 100 degree Celsius.
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