Question

60g of mg reacts with 60g of O2 to yield MgO.
2Mg+02=2MgO
1) what is the limiting reactant?
2) calculate the maximum amount of mgO that can be formed.
3) calculate the amount of one of the reactant which remains unreacted.​

Answer 1

Atomic mass of Mg = 24.30 u,

Atomic mass of O = 16 u,

Molecular mass of O2 = 32 u.

Mass of reactant = Mass of product

60g of mg + 60g of O2 = 120g of MgO.

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