60g of urea dissolved in 180g of h2o .find mole fraction of solvent
Answers
Answered by
0
Answer:
10/11 is the mole fraction of solvent
Explanation:
Mole weight of urea = 60 g
Mole weight of water = 18
no . of moles urea = 60/60 =1
no of moles water = 180/18 = 10
moles fraction of urea = (moles of urea) ÷ (total moles)
=> 1/(10+1)
=>1/11
mole fraction of the solvent = (moles of solvent) ÷ (total moles)
=> 10/11
Answered by
0
Answer:
0.99
Explanation:
formula: x A =na/na+nb. xh2o =nh2o/nh2o +nurea ... nurea =60/60=1 nh2o =180/18 =10 =10 /11 =0.99.....hope its help u...❤TC mark as brain list....
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