60W,100W and 1000W bulbs are connected in parallel to the mains.The bulb that will be brigest is (all of them have same specified voltage
Answers
Explanation:
find out R
R = V^2/P
Voltage same, divided by low value gives high value in answer
So, 60W has high resistance and 1000W has low resistance. Low resistance has high supply of current and high resistance has low value of current.
Therefore 1000W will be the brightest.
Given : 60W,100W and 1000W bulbs are connected in parallel to the mains
To Find : The bulb that will be brightest is
Solution:
P = V²/R
=> R = V²/P
60W,100W and 1000W bulbs
Let say specified (rated) Voltage is Vₙ
A Bulb 60 W
=> Ra = (Vₙ)²/60
B Bulb 100 B
=> Rb = (Vₙ)²/100
C Bulb 100 B
=> Rc = (Vₙ)²/1000
Now all three connected in parallel hence all will get same voltage V
Pa = V²/Ra = V² / (Vₙ)²/60 = 60 ( V/Vₙ)²
Pb = V²/Rb = V² / (Vₙ)²/100 = 100 ( V/Vₙ)²
Pc = V²/Rc = V² / (Vₙ)²/1000 = 1000 ( V/Vₙ)²
Bulb with maximum power will be the brightest
Hence 1000W bulb will be the brightest
Learn More:
calculate energy and power consumed by 8 ohm resistor in one ...
brainly.in/question/10685640
Electricity consumed by a household using incandescent bulb is ...
brainly.in/question/9687864