Question

61. A force is inclined at 60° to the horizontal. If its rectangu
component in the horizontal direction is 50 N, the
magnitude of the force in the vertical direction is​

Answer 1

Answer:

50√3N

Explanation:

as in horizontal direction,f=fcos60°=f/2

f/2=50

f= N

in vertical direction,f=fsin60°

f=100×√3/2

f=50√3N