61. A force is inclined at 60° to the horizontal. If its rectangu
component in the horizontal direction is 50 N, the
magnitude of the force in the vertical direction is
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Answer:
50√3N
Explanation:
as in horizontal direction,f=fcos60°=f/2
f/2=50
f= N
in vertical direction,f=fsin60°
f=100×√3/2
f=50√3N
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