61. A network of five identical resistors, each of
value 25ohm is made as shown in the figure.
Equivalent resistance between points A and
Bis
(a) 125ohm
(b) 50ohm
(c) 25ohm
(d) 15ohm
Answers
Solution :
⏭ Given:
✏ A network of five identical resistors, each of value 25Ω is made as shown in the figure.
⏭ To Find:
✏ Equivalent resistance between points A and B.
⏭ Concept:
✏ In this type of complex circuit question, first we have to simplify complex circuit diagram.
✏ For simplified circuit diagram, see the attachment.
✏ we can see the balanced wheat-stone bridge into simplified circuit diagram.
⏭ Calculation:
- Equivalent resistance of upper arm:
✏ R' = R1 + R3 (series connection)
✏ R' = 25 + 25
✏ R' = 50Ω
- Equivalent resistant of lower arm:
✏ R" = R2 + R4
✏ R" = 25 + 25
✏ R" = 50Ω
- Equivalent resistance between A and B :
✏ R = R'R"/R'R" (parallel connection)
✏ R = 2500/100
✏ R = 25Ω ✔
➡ Additional Information:
✏ For, balanced wheat-stone bridge the given condition is required
- R1/R2 = R3/R4
A network of five identical resistors, each of value 25ohm is made as shown in the figure. Equivalent resistance between points A and B is
The given circuit forms a between point A and B
See the Figure
The bridge is said to be balanced when deflection in galvanometer is zero. i.e and hence ,
Under this condition
Similarly ,
Or
So, this is a condition for which a Wheatstone bridge is balanced .
━━━━━━━━━━━━━━━━━━━━━━━━━
Therefore in this question ,
Answer will be because this is balanced wheatstone bridge between point A and B.