Physics, asked by rahil619, 11 months ago

61. A network of five identical resistors, each of
value 25ohm is made as shown in the figure.
Equivalent resistance between points A and
Bis
(a) 125ohm
(b) 50ohm
(c) 25ohm
(d) 15ohm​

Attachments:

Answers

Answered by Anonymous
7

Solution :

Given:

✏ A network of five identical resistors, each of value 25Ω is made as shown in the figure.

To Find:

✏ Equivalent resistance between points A and B.

Concept:

✏ In this type of complex circuit question, first we have to simplify complex circuit diagram.

✏ For simplified circuit diagram, see the attachment.

✏ we can see the balanced wheat-stone bridge into simplified circuit diagram.

Calculation:

  • Equivalent resistance of upper arm:

✏ R' = R1 + R3 (series connection)

✏ R' = 25 + 25

R' = 50Ω

  • Equivalent resistant of lower arm:

✏ R" = R2 + R4

✏ R" = 25 + 25

R" = 50Ω

  • Equivalent resistance between A and B :

✏ R = R'R"/R'R" (parallel connection)

✏ R = 2500/100

R = 25Ω

Additional Information:

✏ For, balanced wheat-stone bridge the given condition is required

  • R1/R2 = R3/R4
Attachments:
Answered by Anonymous
4

\huge\underline{\underline{\bf \orange{Question-}}}

A network of five identical resistors, each of value 25ohm is made as shown in the figure. Equivalent resistance between points A and B is

\huge\underline{\underline{\bf \orange{Solution-}}}

The given circuit forms a \color{skyblue}\underline{\sf balanced\:Wheatstone\:bridge} between point A and B

See the Figure

The bridge is said to be balanced when deflection in galvanometer is zero. i.e {\sf i_g=0} and hence ,

\implies{\sf V_B=-V_D}

Under this condition

\implies{\sf V_A-V_B=V_A-V_D}

\implies{\sf i_1P=i_2R }

\color{darkblue}\implies{\sf \dfrac{i_1}{i_2}=\dfrac{R}{P}\:\:\:\;→(1) }

Similarly ,

\implies{\sf V_B-V_C=V_D-V_C}

\implies{\sf i_1Q=i_2S}

\color{darkblue}\implies{\sf \dfrac{i_1}{i_2}=\dfrac{S}{Q}\:\:\:\:→(2) }

{\sf From\: Equation\:1\:and\:2-}

\color{red}\implies{\sf \dfrac{R}{P}=\dfrac{S}{Q} }

Or

\color{red}\implies{\sf \dfrac{P}{Q}=\dfrac{R}{S}}

So, this is a condition for which a Wheatstone bridge is balanced .

━━━━━━━━━━━━━━━━━━━━━━━━━

Therefore in this question ,

Answer will be \color{red}\underline{\underline{\sf 25Ω }} because this is balanced wheatstone bridge between point A and B.

Attachments:
Similar questions