Question

61. A particle of mass 2 kg is moving in circular path with constant speed 20 m
when particle travels from A to P will be
with constant speed 20 m/s. The magnitude of change in velocity
JP
(1) 2012 m/s
(2) 40 m/s
(4) Zero
(3) 40/2 m/s​

Answer 1

Answer: The magnitude of change in velocity will be .

Explanation:

Given that,

Mass m = 2 kg

Speed v = 20 m/sec

We taking the components of velocity at A and P

When the particle travels from A to P

The magnitude of change in velocity will be

Hence, The magnitude of change in velocity will be .

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Answer 2

Answer:

no option is seem correct

Explanation:

Answer: The magnitude of change in velocity will be

$20 \sqrt{2}$

.

Explanation:

Given that,

Mass m = 2 kg

Speed v = 20 m/sec

We taking the components of velocity at A and P

$v_{a} = 20icap$

$v _{p} = 20jcap$

When the particle travels from A to P

The magnitude of change in velocity will be

$v = \sqrt{ { v_{p}}^{2} + {v_{a}}^{2} } \: \\ v = \sqrt{ {20}^{2} + {20}^{2} } \\ v = 20 \sqrt{2}$

Hence, The magnitude of change in velocity will be .

$20 \sqrt{2}$