Question

61st term of the h.p. 4/3,3/2,12/7...... is

Answer 1

Answer:

Consider1/6, /14, 1/3, ...... ∞

Here T2 – T1 = T3 – T2 = 1/12 ⇒ 1/6, 1/4, 1/3 is an A.P.

4th term of this A.P. = 1/6 + 3 × 1/12 = 1/6 + 1/4 = 5/12,

And the 8th term = 1/6 + 7 × 1/12 = 9/12.

Hence the 8th term of the H.P. = 12/9 = 4/3 and the 4th term = 12/5.