62 3
2
4. If the perimeter of a triangle is 6
![6? \times \frac{?2}{?3} 6? \times \frac{?2}{?3}](https://tex.z-dn.net/?f=6%3F+%5Ctimes+%5Cfrac%7B%3F2%7D%7B%3F3%7D+)
and the lengths of two of its sides
![2 {?1}{?2} 2 {?1}{?2}](https://tex.z-dn.net/?f=2+%7B%3F1%7D%7B%3F2%7D+)
and 3
![3 \times \frac{?1}{?3} 3 \times \frac{?1}{?3}](https://tex.z-dn.net/?f=3+%5Ctimes+%5Cfrac%7B%3F1%7D%7B%3F3%7D+)
cm, find the length of
3
2
3
the third side.
Answers
Answered by
1
Answer:
Step-by-step explanation:
sum of three sides of triangle = perimeter
21/2 + 31/3 + x = 62/3
21/2 + x = 31/3
x = 31/3 -21/2
x = 62/6 - 63/6
x = -1/6
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