62.5 × 1018 electrons per second are flowing through
a wire of area of cross-section 0.1 m2
, the value of
current flowing will be
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Answered by
8
Answer:As we know
I=
t
Q
where Q=ne(number of electron× charge on each electron which is 1.6×10
−19
)
Therefore,
I=
t
ne
=
1
62.5×10
18
×1.6×10
−19
=10A
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