Question

62.5 x 1018 electrons per second
are flowing through a wire of area
of cross-section 0.1m2, the value
of current flowing will be:
А
1A
B
0.1A
с
10A
0.11 A​

Answer 1

Answer:

c) 10A

Explanation:

As we know

I=

t

Q

where Q=ne(number of electron× charge on each electron which is 1.6×10

−19

)

Therefore,

I=

t

ne

=

1

62.5×10

18

×1.6×10

−19

=10A