Question

62. A dealer sells two cycles at a price of Rs. 616 each. In this transaction
he earns 12% profit on one cycle and suffer 12% loss on the other
cycle. Find the percentage loss or profit in the whole deal. ​

Answer 1

Selling Price of two cycles =1188 Rs each

Total selling price =1188×2=2376 Rs

Trader gains 30% on first cycle.

Let's assume CP of cycle =x Rs

Then, SP=CP+CP×100Gain Percentage

⇒1188=x+x×10030

⇒1188=1013x

∴x=131188×10=1311880 Rs

Also, trader loses 30% on another cycle.

Let's assume CP of this cycle =y Rs

Then, SP=CP−CP×100Loss Percentage

⇒1188=y−y×10030

⇒1188=107y

∴y=71188×10=711880 Rs

Hence, Total CP = x+y=13

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Answer 2

Answer:

rs. 18 loss

Explanation:

Total S.P. = Rs. 616+616 = Rs. 1232

Let C.P. of P%= 12 be x

Let C.P. of L%= 12 be y

S.P.= (1+12/100) ^ x

616= 112/100 ^ x

x= 616^ 100/112

x= 550

S.P.= (1-12/100) ^ y

616= 88/100 ^ y

y= 616^ 100/88

y= 700

Total C.P. = x+y = 550+ 700= 1250

Loss= C.P.- S.P.

= 1250- 1232

= Rs. 18 loss

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