Question

62. Assertion : If both zeroes of 1 point polynomial x2 - 2kx + 2 are equal in magnitude but opposite in sign, then value of k is 1/2 Reason: Product of zeroes of quadratic polynomial; p(x) =ax2 +bx + C, at O is cla*

Both (A) and (R) are true and (R)is correct reason of (A)

Both (A) and (R) are true but (R) is not a correct reason of (A)

(A) is true but (R) is false

(A) is false but (R) is true​

Answer 1

Both (A) and (R) are true and (R)is correct reason of (A)

Answer 2

Given : . Assertion : If both zeroes of  polynomial x² - 2kx + 2 are equal in magnitude but opposite in sign, then value of k is 1/2

Reason: Product of zeroes of quadratic polynomial; p(x) =ax²+bx + c,  is c/a

To Find :   Choose correct option:

Both (A) and (R) are true and (R)is correct reason of (A)

Both (A) and (R) are true but (R) is not a correct reason of (A)

(A) is true but (R) is false

(A) is false but (R) is true​

Solution:

polynomial x² - 2kx + 2

both zeroes are equal in magnitude but opposite in sign

let say  α  and -α

sum of zeroes = α  -α =  0

 sum of zeroes = -(-2k)/1  = 2k

2k = 0

=> k = 0

Hence k = 1/2  is incorrect

(A) is false

Product of zeroes of quadratic polynomial; p(x) =ax²+bx + c,  is c/a

TRUE

(R) is true​

so correct option is  (A) is false but (R) is true​

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