Question

62. Oxidation number of H NaH.CaH, and LiH respectively
(a) +1, 1.-1
(c) +1, +1+1
(b) -1, +1, +1
(d) -1,-1.-1​

first and correct answer will be marked as brainiest

Answer 1

Answer:

(d)-1,-1,-1

Explanation:

the oxidation state of hydrogen is +1 in its compounds except for metal hydrides such as NaH LiH etc.

Answer 2

OPTION (D) IS CORRECT.

(D) -1, -1, -1

Explanation:

• The oxidation number is the number of electrons that an element can share/lose/gain. It is associated by number of bonds an element can make.
• An atom has 0 oxidation number. Monoatomic ions has oxidation number equal to its valence.
• When hydrogen is bonded to less electronegative atom, it has an oxidation number of -1. Sodium, calcium, and lithium are less electronegative than hydrogen.
• Oxidation number of H in $NaH, CaH_{2} , LiH$ are $-1,-1,-1$. Therefore, option (D) is correct.
• It is calculated as shown in picture: