62. The average of 20 numbers is zero. Of them, at the most, how many numbers may
be greater than zero ?
(A) 19
(B) 1
(C) 10
(D) O
Answers
Answered by
2
Answer:
option c is correct answer
Step-by-step explanation:
Let the 20 numbers be a
1
,a
2
,...,a
20
Given that average of 20 numbers is zero.
Therefore,
20
a
1
+a
2
+...+a
20
=0
⟹a
1
+a
2
+...+a
20
=0
⟹a
1
+a
2
+...+a
19
=−a
20
Therefore, at the most 19 numbers can be greater than zero.
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