6243/2cube *5 power 4 will terminates after how many decimals
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AFTER TWO DECIMAL PLACES,IT WILL TERMINATE.
BECAUSE
(6243)^2/(2)^2×(5)^4
FIRST,I CHANGE THE DENOMINATOR IN THE FORM OF 2^M×5^M.
(6243)^2/(2)^2×(5)^4×(5)2/(5)2
(6243)^2×(5)^4×(5)2/(2)^2×(5)^2
THEN BY USING THE IDENTITY
A^M×B^M=(A×B)^M
I GET,
(6243)^2×(5)^4×(5)^2/(10)^2
(6243)^2×(5)^4×(5)^2/100.
THE DENOMINATOR IS 100.SO,AFTER TWO PLACES IT WILL TERMINATE.
BECAUSE
(6243)^2/(2)^2×(5)^4
FIRST,I CHANGE THE DENOMINATOR IN THE FORM OF 2^M×5^M.
(6243)^2/(2)^2×(5)^4×(5)2/(5)2
(6243)^2×(5)^4×(5)2/(2)^2×(5)^2
THEN BY USING THE IDENTITY
A^M×B^M=(A×B)^M
I GET,
(6243)^2×(5)^4×(5)^2/(10)^2
(6243)^2×(5)^4×(5)^2/100.
THE DENOMINATOR IS 100.SO,AFTER TWO PLACES IT WILL TERMINATE.
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