625 × 128 × 243 Prime factors in exponential from
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Start with the smallest prime number that divides into 72, in this case 2. We can write 72 as:
72 = 2 x 36
Now find the smallest prime number that divides into 36. Again we can use 2, and write the 36 as 2 x 18, to give.
72 = 2 x 2 x 18
18 also divides by 2 (18 = 2 x 9), so we have:
72 = 2 x 2 x 2 x 9
9 divides by 3 (9 = 3 x 3), so we have:
72 = 2 x 2 x 2 x 3 x 3
2, 2, 2, 3 and 3 are all prime numbers, so we have our answer.
In short, we would write the solution as:
72 = 2 x 36
72 = 2 x 2 x 18
72 = 2 x 2 x 2 x 9
72 = 2 x 2 x 2 x 3 x 3
72 = 23 x 32 (prime factorization exponential form)
72 = 2 x 36
Now find the smallest prime number that divides into 36. Again we can use 2, and write the 36 as 2 x 18, to give.
72 = 2 x 2 x 18
18 also divides by 2 (18 = 2 x 9), so we have:
72 = 2 x 2 x 2 x 9
9 divides by 3 (9 = 3 x 3), so we have:
72 = 2 x 2 x 2 x 3 x 3
2, 2, 2, 3 and 3 are all prime numbers, so we have our answer.
In short, we would write the solution as:
72 = 2 x 36
72 = 2 x 2 x 18
72 = 2 x 2 x 2 x 9
72 = 2 x 2 x 2 x 3 x 3
72 = 23 x 32 (prime factorization exponential form)
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