Math, asked by saazizsk163, 7 months ago

625:15,625; 3,90,625;​

Answers

Answered by llSᴡᴇᴇᴛHᴏɴᴇʏll
5

Answer:

Finding the HCF of 625 and third number 15625 by applying Euclid's division lemma. Now, the remainder at this stage is zero. So the divisor i.e., 625 at this stage is the HCF of 625 and 15625. Hence, HCF of (626, 3127, 15628) is 625.

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