Math, asked by vipinjaatrathi, 1 year ago

625 principal 4% rate 2year calculate the amount and the compound intrest

Answers

Answered by ans81
10
HEY MATE HERE IS YOUR ANSWER
______________
Principal : ₹ 625
Rate : 4% p.a
Time : 2 years
______________

We know :-
-------------

 = > A = p(1 + r /100{)}^{n}

 = > A = 625(1 + 4 /100 {)}^{2}

 => A = 625(5{)}^{2}

=> A = 625 × 25+1/100^2

➡️ A = 625 × 676 / 625

➡️ A = 676

Compound interest =

P - A = 676 - 625

C.I = 51 ₹

______________________

Hope it will help you

supreet4444: hii
Answered by BloomingBud
20
\mathbb { SOLUTION }

Principal (P) = Rs.625
Rate of interest (R) = 4% per annum
Time (n) = 2 years

We know that,

Amount(A) = P {(1 + \frac{R}{100} )}^{n} \\ \\ Amount(A) = 625 {(1 + \frac{4}{100}) }^{2} \\ \\ Amount(A) = 625 {(1 + \frac{1}{25} )}^{2} \\ \\ Amount(A) = 625 {( \frac{25 + 1}{25} )}^{2} \\ \\ Amount(A) = 625 {( \frac{26}{25} )}^{2} \\ \\ Amount(A) = 625 \times \frac{676}{625} \\ \\ Amount(A) = 676

Hence, the amount (A) = \bf {Rs.676}

Now,

C.I = Amount - Principal

C.I = 676 - 625

C.I = Rs.51

Hence,
Compound Interest (C.I) = Rs.51

supreet4444: hii
Similar questions