Question

( 625 z⁴ - 1) using identities




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Answer 1

Answer:

$( {25z}^{2}) ^{2} - 1$

$= ( {25z}^{2} - 1)( {25z}^{2} + 1)$

$= ( ({5z)}^{2} - 1)( {25z}^{2} + 1)$

$(5z - 1)(5z + 1)( {25z}^{2} + 1)$

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