Question

627 divisibility test by 7​

Answer 1

Answer:

To check if a number is evenly divisible by 7

• Take the last digit of the number
• Double it
• Then subtract the result from the rest of the number
• If the resulting number is evenly divisible by 7, so is the original number.

Now

• The last digit of 627 is 7
• Double it = 2× 7 = 14
• Then subtract the result from the rest of the number 62 - 14 = 38
• If the resulting number is evenly divisible by 7, so is the original number. Since 38 is not divisible by 7 so is 627

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