Math, asked by vallinswami, 7 days ago

629 prime factorization​

Answers

Answered by pradeepbabita101
2

Step-by-step explanation:

Solution: Since, the prime factors of 629 are 17, 37. Therefore, the product of prime factors = 17 × 37 = 629.

Answered by shadabimam2501
1

Answer:

hope its help you

Step-by-step explanation:

To find the factors of 629, we will have to find the list of numbers that would divide 629 without leaving any remainder.

629/37 = 17; therefore, 37 is a factor of 629 and 17 is also a factor of 629.

629/629 = 1; therefore, 629 is a factor of 629 and 1 is also a factor of 629.

Similarly we can find other factors. Hence, the factors of 629 are 1, 17, 37, 629.

☛ Also Check:

Factors of 45 - The factors of 45 are 1, 3, 5, 9, 15, 45

Factors of 72 - The factors of 72 are 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72

Factors of 34 - The factors of 34 are 1, 2, 17, 34

Factors of 125 - The factors of 125 are 1, 5, 25, 125

Factors of 9 - The factors of 9 are 1, 3, 9

Factors of 629 by Prime Factorization

The number 629 is composite and therefore it will have prime factors. Now let us learn how to calculate the prime factors of 629. The first step is to divide the number 629 with the smallest prime factor, here it is 17. We keep dividing until it gives a non-zero remainder.

629 ÷ 17 = 37

Further dividing 37 by 17 gives a non-zero remainder. So we stop the process and continue dividing the number 37 by the next smallest prime factor. We stop ultimately if the next prime factor doesn't exist or when we can't divide any further.

So, the prime factorization of 629 can be written as 171 × 371 where 17, 37 are prime.

Please help me

I need 30 Brainleast answer please help me

Please Mark me Beainleast please help me

Similar questions