62x+37y=13
37x+62y= -112
solve the pair of linear equation
Answers
Answered by
20
hey mate ur answer is in attachment.... ; hope it will help you... ☺☺
Attachments:
Bunti360:
Shortcut : Subtract both the given equations, Now, Divide 25 on both sides, You will get x-y = 5, Now x = y+5 and keep this in any one of the equation ! Now you will get the answer ! - Just the shortest method I found !..
ok
Answered by
28
Here is the Solution :
Given Equations :
(1) 62x + 37y = 13,
(2) 37x + 62y = -112,
Subtract (2) from (1),
=> (1) - (2)
=> (62x-37x) + (37y-62y) = (13-(-112))
=> 25x - 25y = 125,
Dividing 25 on both sides,
=> x - y = 5,
=> x = 5 + y, ------ (3)
Substituting (3) in (1)
=> (62(y+5)) + 37y = 13,
=> 62y + 310 + 37y = 13,
=> 99y = -297,
=> y = -3, -----(4),
Substituting (4) in (3)
=> x = 5 + (-3)
=> x = 5 - 3
=> x = 2,
Therefore :
x = 2, and,
y = -3 !!..
So therefore we found the values of x and y i.e We solved the pair of linear Equations !.
If you have another easiest method please do notify me !.
Hope you understand, Have a Great day !.
Thanking you, Bunti 360 !..
Given Equations :
(1) 62x + 37y = 13,
(2) 37x + 62y = -112,
Subtract (2) from (1),
=> (1) - (2)
=> (62x-37x) + (37y-62y) = (13-(-112))
=> 25x - 25y = 125,
Dividing 25 on both sides,
=> x - y = 5,
=> x = 5 + y, ------ (3)
Substituting (3) in (1)
=> (62(y+5)) + 37y = 13,
=> 62y + 310 + 37y = 13,
=> 99y = -297,
=> y = -3, -----(4),
Substituting (4) in (3)
=> x = 5 + (-3)
=> x = 5 - 3
=> x = 2,
Therefore :
x = 2, and,
y = -3 !!..
So therefore we found the values of x and y i.e We solved the pair of linear Equations !.
If you have another easiest method please do notify me !.
Hope you understand, Have a Great day !.
Thanking you, Bunti 360 !..
Similar questions