Question

63,0 kg load is raised to 8,9m a height in 1,0 a second. Calculate the magnitude of the constant force used.

Answer 1

Answer:

Force =m

t

(v−u)

=m⋅a

Displacement =

2a

(v

2

−u

2

)

Word done (W) = Force × Displacement

=m⋅a⋅

2a

(v

2

−u

2

)

W =

2

1

m(v

2

−u

2

)

W =

2

1

×20×(2500−1600)

=

2

1

×20×900

=9000J

Therefore, the work done to attain the final velocity is 9000J

Video Explanation