Question

63÷[{(3^2-3^0)-(2^0+1^2)}]

Answer 1

just use BODMAS bro it will be done

Answer 2

63÷[{(3^2-3^0)-(2^0+1^2)}]

=63÷[{(9-1)-(1+1)}]

=63÷(8-2)

=63/6

=21/2