Question

63-[(-3) {-2-5}]÷[3{5+(-2) (-1)}]​

Answer 1

Answer:

$\boxed{62}$

Step-by-step explanation:

$\sf Simplify \: the \: following: \\ \sf \implies 63 - \frac{[(-3) (-2-5)]}{[3(5 + ( - 2)( - 1))]} \\ \\ \sf - 2 - 5 = - 7 : \\ \sf \implies 63 - \frac{[(-3) \boxed{ - 7}]}{[3(5 + ( - 2)( - 1))]} \\ \\ \sf ( - 2) \times ( - 1) = 2 : \\ \sf \implies 63 - \frac{[(-3) ( - 7)]}{[3(5 + \boxed{2})]} \\ \\ \sf 5 + 2 = 7 : \\ \\ \sf \implies 63 - \frac{[(-3) ( - 7)]}{[3( \boxed{7})]} \\ \\ \sf ( - 3) \times ( - 7) = 21 : \\ \sf \implies 63 - \frac{ \boxed{21}}{3 \times 7} \\ \\ \sf 3 \times 7 = 21 : \\ \sf \implies 63 - \frac{ 21}{ \boxed{ 21}} \\ \\ \sf \frac{21}{21} = 1 : \\ \sf \implies 63 - 1 \\ \sf \implies 62$

Additional information:

$\sf (+ ) .(+ ) = ( + ) \\ \\ \sf ( + ).( - ) = ( - ) \\ \\ \sf ( - ).( + ) = ( - ) \\ \\ \sf ( - ).( - ) = ( - ) \\ \\ \sf ( + ) \div ( + ) = ( + ) \\ \\ \sf ( - ) \div ( + ) = ( - ) \\ \\ \sf ( + ) \div ( - ) = ( - ) \\ \\ \sf ( - ) \div ( - ) = ( + )$

$\sf BODMAS \: Rule : \\ \sf B =Brackets \\ \sf O = Orders\\ \sf D =Division \\ \sf M = Multiplication \\ \sf A = Addition\\ \sf S = Subtraction$

Answer 2

Answer:

62

Step-by-step explanation: