Question

63.5g of cu combine with different amount of oxygen to form CU and cu2o then the ratio of oxygen in both the cases??
Answer is urgent ​

Answer 1

Answer:

Here is the answer

Explanation:

This law states that: When two elements combine to form two or more compounds, the weight of one of the elements, which combines with a fixed weight of the other, bear a simple whole number ratio. For example, copper and oxygen may react to give either cuprous oxide (Cu2O) or cupric oxide (CuO), respectively.

Answer 2

Answer:

2:1

Explanation:

2Cu+O2=2CuO

4Cu+ O2=2Cu2O

We know that mass of O=16u & mass of Cu=63.5u.

In Cu2O& CuO if we fix the mass of Oxygen as 16 then the ratio of mass of Cu in both the oxides will be

2.63.5:63.5

127:63.5 which is 2:1

This is a simple whole number ratio hence these compounds follow law of multiple proportions