Question

63. a bag contains 8 red balls and x blue balls, the odd against drawing a blue ball are 2:5.What is the value of x?

Answer 1

Let the total nom of balls be y.
So, 8:x::2:5
Or, 8*5 = 2*y
Or, y= 40/2 = 20.
No. of blue balls = 20 - 8 = 12.

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