Question

63. A body of 10 kg is acted by a force of 129.4 Nif g= 9.8 m/sec?. The acceleration of the
block is 10 m/s2. What is the coefficient of kinetic friction
(a) 0.03
(b) 0.01
(C) 0.30
(d) 0.25​

Answer 1

Answer:

(C) 0.30

Explanation:

F - f = ma

=> umg = F - ma

=> u = F/mg - a/g = (F/m - a)/g

= (129.4/10 - 10)/9.8

= 2.94 / 9.8

= 0.3