63. Amitabh plays a game of tossing a dice. If the number less than 3 appears, he is getting Rs. a, otherwise he has to pay Rs, 10. If the game is fair play
Answers
Answered by
2
Answer:
(i) K
p
=
[NH
3
]
2
[H
2
]
3
[N
2
]
=[
[N
2
][H
2
]
3
[NH
3
]
2
]
−1
=(41)
−1
=
41
1
=0.024 atm
2
(∵
[N
2
][H
2
]
3
[NH
3
]
2
=41)
(ii) K
p
=
[H
2
]
3/2
[N
2
]
1/2
[NH
3
]
=[
[H
2
]
3
[N
2
]
[NH
3
]
2
]
1/2
=(41)
1/2
=6.4 atm
−1
(iii) K
p
=
[N
2
]
2
[H
2
]
6
[NH
3
]
4
=[
[N
2
][H
2
]
3
[NH
3
]
2
]
2
=(41)
2
=1.681×10
3
atm
−4
.
Step-by-step explanation:
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Answered by
29
Answer:
Sample space = { 1,2,3,4,5,6 }
Probab of getting less than 3 = 2/6
Probab of getting any other No's =4/6
Therefore
Total a rs earned = 2/6 * a
Total 10 rs lost = 4/6 * 10
Given that the game is fair
That means no loss or profit
I.e.
Total earned + ( -total lost ) = 0
Since lost that's why we using -ve sign here
Therefore
2a/6 + ( -40/6 ) = 0
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