Question

63. Find the area of triangle ABC with vertices are A(4,2), B(3,9) and C(10, 10)​

Answer 1

$= \frac{1}{2} |4(9 - 10) + 3(10 - 2) + 10(2 - 9)| \\ = \frac{1}{2} \times |4 \times ( - 1) + 3 \times 8 + 10 \times ( - 7)| \\ = \frac{1}{2} | - 4 + 24 - 70| \\ = \frac{1}{2} | - 50| \\ = \frac{1}{2} \times 50 \\ = 25$

hope it helps you.

Answer 2

Answer:

its the answer

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