Question

63 % nitric solution has density 1.80g/ml Calculate molarity molality mole fraction ​

Answer 1

Explanation:

63 % of nitric solution mean

63g weight of solute in 100 gm of solution

molar masss of HNO3=63

no of moles of solute= wt of solute/molar mass

= 63/63=1

weight of solvent = 100-63=37

density=mass of solution/ volume of solution

1.80=100/v

volume of solution= 55.55ml

molarity= number of moles of solute/volume of solution in litre

M=1/(55/1000) =18.18molar

molality= no of moles of solute/weigth of solvent in kg

molality=1/37/1000=27.02

mole fraction of solute= 1/(1+37/18) =0.372

mole fraction of solvent =1-0.372=0.632