Question

63/x + 72/x+6 = 3 find the roots of equations​

Answer 1

Answer:

Step-by-step explanation:

63/x + 72/(x+6) = 3

lets take LCM for x & x+6 = x^2 + 6x

[63(x+6) + 72(x)]/(x^2+6x) = 3

63x+378+72x = 3(x^2+6x)

135x + 378 = 3x^2+18x

3x^2 - 117x - 378

whole eqution be cancel with 3

x^2 - 29x - 126

Answer 2

Answer:

The roots of the given equation are 42 and -3