Question

63a^3 ^2c^5/-7a^2b^2c^5​

Answer 1

Answer:

-9a

Step-by-step explanation:

$=\frac{63a^3b^2c^5}{-7a^2b^2c^5}\\\\\\=\frac{(7a^2b^2c^5)(9a)}{(7a^2b^2c^5)(-1)}\\\\\\=\frac{9a}{-1}\\\\\\Multiply~both~by~-1\\\\\\=\frac{9a*-1}{-1*-1}\\\\\\=\frac{-9a}{1}\\\\\\=-9a$