63a2-112b2 How do we factorize this using suitable identity? Please Answer as fast as possible.
Answers
Answered by
132
Answer:
7(3a + 4b)(3a - 4b)
Step-by-step explanation:
63a² - 112b²
Take out 7 as the common factor:
= 7(9a² - 16b²)
Write in perfect squares:
= 7( (3a)² - (4b)²)
Apply a² - b² = (a + b)(a - b):
= 7(3a + 4b)(3a - 4b)
Answer: 7(3a + 4b)(3a - 4b)
Answered by
42
Answer:
=7(3a+4b)(3a-4b)
Step-by-step explanation:
The given equation is
63a² - 112b²
We have to solve this equation
as we know that both the terms are divisible by 7
so taking 7 common from both values
= 7(9a² - 16b²)
=7((3a)²-(4b)²)
as we know that (a)²-(b)²=(a+b)(a-b)
the given equation becomes
=7(3a+4b)(3a-4b)
which is the factorized form of equation
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