Question

63a²b²-7 Help me I am telling its correct answer But I don't know how to solve it ....
ANSWER

7(3ab-1) (3ab+1)


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Answer 1

$63 {a}^{2} {b}^{2} - 7$

$= 7(9 {a}^{2} {b}^{2} - 1)$

$= 7((3ab)^{2} - {(1)}^{2} )$

$= 7(3ab - 1)(3ab + 1)$

I hope you understood.

Answer 2

Step-by-step explanation:

first take 7 common from both the terms

then express them as whole square form

then apply (a2-b2) formula....

(a2-b2) = (a+b) (a-b)

hope it helps