Question

63apower 2 - 112bpower 2​

Answer 1

Answer:

First of all there is no square root of 63 and 112 so, we must take the common numbers..

i.e. ( 3 * 3 * 7 * a * a ) - ( 2 * 2 * 2 * 2 * 7 * b * b )

Taking the common factors we'll get 7 ( 9 a^2 - 16 b^2 )

= 7 ( 3a^2 - 4b^2 )

And your final answer will be 7 ( 3a - 4b ) ( 3a + 4b )

Hope it helped...

Answer 2

Answer:

write question nicely

please